Answer:
0.12 mol KCl
Explanation:
2 KClO3 (s) 2 KCl (s) + 3 O2 (g)
15 g x mol
x g KCl = 15 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]
x g KCl = 0.12 mol KCl
Answer:
0.1224 moles
Explanation:
this is a decompostion reaction
Equation of reaction
2KClO₃ → 2KCl + 3O₂
molar mass of KClO₃ =
molar mass of K = 39.09g/mol
Molar mass of Cl = 35.5g/mol
Molar mass of O = 15.99g/mol
Molar mass of KClO3 = [39 + 35.5 + (3*15.99)]
Molar mass of KClO3 = 122.47g/mol
From the equation of reaction,
2 moles of KClO₃ produces 2 moles of KClO₃
But 1 mole = molar mass
1 mole of KClO₃= 122.47g
2 moles of KClO₃ = 2 * 122.47 = 244.94g
If 244.94g of KClO₃ produces 2 moles of KCl
15 g of KClO₃ will produce x mole of KCl
x = (15 * 2) / 244.94
x = 0.1224moles
15g of KClO₃ will produce 0.1224moles of KCl
