Question

Write an expression for the area of this shape. Expand and simplify the expression.

Answer 1

Expression for the area of the shape ( right angled triangle ) is $Area =(x^2+3x)$ .

Step-by-step explanation:

Here we have , a right angled triangle with given dimensions:

$Perpendicular = 2x$

$Base = x+3$

Also ,it's known to us that area of right angled triangle = $\frac{1}{2} (base)(height)$ . Let's find out area of this given right angled triangle in figure with the dimensions

$Perpendicular = 2x$

$Base = x+3$

Area = $\frac{1}{2} (base)(height)$

⇒ $Area = \frac{1}{2} (base)(height)$

⇒ $Area = \frac{1}{2} (base)(Perpendicular)$

⇒ $Area = \frac{1}{2} (x+3)(2x)$

⇒ $Area = \frac{1}{2} (2x^2+3(2x))$

⇒ $Area = \frac{1}{2} (2x^2+6x)$

⇒ $Area = \frac{1}{2} (2)(x^2+3x)$

⇒ $Area =(x^2+3x)$

Therefore, Expression for the area of the shape ( right angled triangle ) is $Area =(x^2+3x)$ .