Respuesta :
Answer:
0.0548
Step-by-step explanation:
The distribution of life span for a certain type of battery is approximately normal with mean 2.5 hours and standard deviation 0.25 hour.
To find the the probability that a selected battery will have a life span of at most 2.1 hours, we need to first determine the z-score for x=2.1 hours using
[tex]z = \frac{x - \mu}{ \sigma} [/tex]
We substitute the values to get:
[tex]z = \frac{2.1 - 2.5}{0.25} = - 1.6[/tex]
We read read -1.6 from the standard normal distribution table to get:
P(X≤2.1)=0.0548
The probability that the selected battery will have a life span of at most 2.1 hours is 0.0548.
Given information:
The life span of a battery is the amount of time the battery will last.
The distribution of life span for a certain type of battery is approximately normal with a mean of 2.5 hours and a standard deviation of 0.25 hours.
The z-value for the probability that the selected battery will have a life span of at most 2.1 hours will be calculated as,
[tex]z=\dfrac{x-\mu}{\sigma}\\z=\dfrac{2.1-2.5}{0.25}\\z=-1.6[/tex]
Now, use the standard normal distribution table or curve to get the value of required probability as,
[tex]P(x=2.1)=0.0548[/tex]
Therefore, the probability that the selected battery will have a life span of at most 2.1 hours is 0.0548.
For more details, refer to the link:
https://brainly.com/question/15103234