Answer:
Period ⇒ 40
Amplitude ⇒ 12
Mid-line ⇒ 32
Step-by-step explanation:
The table is counting by 4's and the period is the amount of space between 2 peaks. In this scenario, we can find the peaks by looking for two of the same highest value (44). We can see that x=40 has a value of 44 while the other is actually not shown because it would be located at x=0. Therefore the period is 40
The amplitude can be found by using the following:
[tex]\frac{1}{2}|max - min|[/tex]
Our maximum is 44 and our minimum is 20.
[tex]\frac{1}{2}|44 - 20|[/tex]
[tex]\frac{1}{2}|24|[/tex]
[tex]\frac{1}{2}(24)[/tex]
The amplitude is 12
The amplitude is the distance from the peak to the mid-line. To find the mid-line, we can either subtract our amplitude from our maximum value (44) or add our amplitude to our minimum value (20)
44 - 12 = 32
20 + 12 = 32
Therefore our mid-line is y = 32
~Hope this helps!~
