Respuesta :

Answer:

Maximum magnetic force on current carrying wire when wire is placed at 90 degree with magnetic field

Explanation:

As we know that the magnetic force on current carrying conductor is given as

[tex]\vec F = i(\vec L \times \vec B)[/tex]

here we have

[tex]F = i L Bsin\theta[/tex]

here we know that

[tex]\theta [/tex] = angle between length vector and magnetic field vector

so if we would like to have maximum magnetic force on the current carrying wire then

[tex]\theta = 90 [/tex]

so we have

[tex]F_{mex} = iLB[/tex]

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