Answer:
8 units.
Step-by-step explanation:
We have been given that Tom's house is located at point (-2, 3) and the school is located at point (-2, -5). We are asked to find the distance between Tom's house and the school.
We will use distance formula to solve our given problem.
[tex]D=\sqrt{x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Let point [tex](-2,3)=(x_1,y_1)[/tex] and point [tex](-2,-5)=(x_2,y_2)[/tex].
Upon substituting the coordinates of given points in distance formula, we will get:
[tex]D=\sqrt{(-2-(-2))^2+(-5-3)^2}[/tex]
[tex]D=\sqrt{(-2+2)^2+(-8)^2}[/tex]
[tex]D=\sqrt{0+64}[/tex]
[tex]D=8[/tex]
Therefore, the distance between Tom's house and the school is 8 units.
