Respuesta :
Answer:
The value of money in the wallet of Charmaine ( x ) = $ 18
The value of money in the wallet of dale ( y ) = $ 26
The value of money in the wallet of Justin ( z ) = $ 72
Step-by-step explanation:
Let Money in the wallet of Charmaine = x
Money in the wallet of dale = y
Money in the wallet of Justin = z
Total money = $ 116
⇒ x + y + z = $ 116 ------- ( 1 )
Dale has $ 8 more than Charmaine.
⇒ y = 8 + x ----------------- ( 2 )
Justin has 4 times what Charmaine has.
⇒ z = 4 x -------------------- ( 3 )
Put the values of y and z in equation (1), we get
⇒ x + 8 + x + 4 x = 116
⇒ 6 x = 116 - 8 = 108
⇒ x = [tex]\frac{108}{6}[/tex]
⇒ x = $ 18
This is the value of money in the wallet of Charmaine.
Put the value of x in equation (2) we get,
⇒ y = 8 + 18
⇒ y = $ 26
This is the value of money in the wallet of dale.
Money in the wallet of Justin z = 4 x
⇒ z = 4 × 18
⇒ z = $ 72
This is the value of money in the wallet of Justin.
Answer:
The amount Charmaine has $18, Dale has $26 and Justin has $72.
Step-by-step explanation:
Given:
Charmaine , dale , and Justin have a total of 116$ in their wallets. Dale has 8$ more than charmaine. Justin has 4 times what charmaine has.
Now, to find each have.
Let the amount of Charmaine be [tex]x.[/tex]
So, the amount of Dale has = [tex]x+8.[/tex]
And, the amount of Justin has = [tex]4x.[/tex]
The total amount of Charmaine , dale and Justin have = $116.
Now, to get the amount of each we put an equation:
[tex]x+(x+8)+(4x)=116[/tex]
[tex]x+x+8+4x=116[/tex]
[tex]6x+8=116[/tex]
Subtracting both sides by 8 we get:
[tex]6x=108[/tex]
Dividing both sides by 6 we get:
[tex]x=18.[/tex]
The amount Charmaine has = $18.
Now, substituting the value of [tex]x[/tex]:
[tex]x+8\\\\=18+8\\\\=26.[/tex]
The amount Dale has = $26.
[tex]4x\\\\=4\times 18\\\\=72.[/tex]
The amount Justin has = $72.
Therefore, the amount Charmaine has $18, Dale has $26 and Justin has $72.
