The population of New Mexico in the mid-2000 will approximately be 103,917,600.
Step-by-step explanation:
Step 1:
Mexico's population in mid-1994 was 91,800,000. It increases by 2.2% a year. So we need to calculate how much 2.2% of 91,800,000 is.
2.2% of 91,800,000[tex]= \frac{2.2}{100} (91,800,000) = 0.022 (91,800,000)=2,019,600.[/tex]
So with every year, the previous year's population increases by 2,019,600.
Step 2:
The population in 1994 [tex]= 91,800,000.[/tex]
The population in 1995 [tex]= 91,800,000 + 2,019,600= 93,819,600.[/tex]
The population in 1996 [tex]= 93,819,600 + 2,019,600= 95,839,200.[/tex]
The population in 1997 [tex]= 95,839,200 + 2,019,600= 97,858,800.[/tex]
The population in 1998 [tex]= 97,858,800 + 2,019,600= 99,878,400.[/tex]
The population in 1999 [tex]= 99,878,400 + 2,019,600= 101,898,000.[/tex]
The population in 2000 [tex]= 101,898,000 + 2,019,600= 103,917,600.[/tex]
The population of New Mexico in the mid-2000 will approximately be 103,917,600.
