She wishes to estimate the proportion of horses with enteroliths who are fed at least two flakes of alfalfa per day. In a sample of 62 horses with enteroliths, she finds 42 are fed two or more flakes of alfalfa. She estimates the standard error to be:

0.0594.
0.0035.
0.2185.
0.4675.

Respuesta :

Answer:

0.0594.

Step-by-step explanation:

The standard error of a proportion p, in a sample of size n, is given by:

[tex]SE_{p} = \sqrt{\frac{p(1-p)}{n}}[/tex]

In a sample of 62 horses with enteroliths, she finds 42 are fed two or more flakes of alfalfa.

This means that [tex]n = 62, p = \frac{42}{62} = 0.6774[/tex]

So

[tex]SE_{p} = \sqrt{\frac{p(1-p)}{n}}[/tex]

[tex]SE_{p} = \sqrt{\frac{0.6774*0.3226}{62}} = 0.0594[/tex]

So the correct answer is:

0.0594.

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