Answer:
Step-by-step explanation:
a) H0: [tex]\bar x = 24.57[/tex]
Ha: [tex]\bar x \neq 24.57[/tex]
(Two tailed test at 5% significance level)
b) n=30
Mean difference = [tex]23.89-24.57 = - 0.68[/tex]
Std error of mean = [tex]\frac{s}{\sqrt{n} } \\=\frac{2.40}{\sqrt{30} } \\=0.4382[/tex]
b) Test statistic t = mean diff/std error = -1.552
df = 30-1 =29
p value=0.0657
c) Since p > 0.05 our signi. level, we accept null hypothesis.
There is no significant difference between the means.
d) Using critical value we find that test statistic is > critical value left
So accept H0