Answer:
Mass of water = 21.6 g
Explanation:
Given data:
Mass of C₂H₆ = 15 g
Mass of O₂ = 45 g
Mass of water produced = ?
Solution:
Chemical equation:
2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O
Number of moles of C₂H₆:
Number of moles = mass/ molar mass
Number of moles = 15 g/ 30 g/mol
Number of moles = 0.5 mol
Number of moles of O₂ :
Number of moles = mass/ molar mass
Number of moles = 45 g/ 32 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of C₂H₆ and O₂ with H₂O.
C₂H₆ : H₂O
2 : 6
0.5 : 6/2×0.5 = 1.5
O₂ : H₂O
7 : 6
1.4 : 6/7×1.4 = 1.2
The number of moles of water produced by oxygen are less so it will limiting reactant.
Mass of water produced:
Mass = number of moles × molar mass
Mass = 1.2 mol × 18 g/mol
Mass = 21.6 g
