Question

Which solution listed below yields the highest molar concentration? 121.45 g of KOH in 75.0 mL 23.49 g of NH4OH in 125.0 mL 217.5 g of LiNO3 in 2.00 L 15.25 g of Pb(C2H3O2)2 in 65.0 mL

Answer 1

Answer:

The answer to your question is KOH (28.9 M)

Explanation:

Data

a) 121.45 g of KOH vol 75 ml

Molar mass = 39 + 16 + 1 = 56 g

                       56g --------------- 1 mol

                    121.45 g -----------  x

                       x = (121.45 x 1)/56

                       x = 2.169 g

Molarity = 2.169 / 0.075

Molarity = 28.9 M

b) 23.49 g of NH₄OH vol 125 ml

Molar mass = 14 + 5 + 16 = 35 g

                      35 g --------------- 1 mol

                    23.49 g ------------ x

                      x = 0.67 moles

Molarity = 0.67 / 0.125

Molarity = 5.4 M                        

c) 217.5 g of LiNO₃ in 2L

Molar mass = 7 + 14 + 48 = 69 g

                       69 g ----------------- 1 mol

                    217.5 g ---------------- x

                      x = 3.15 moles

Molarity = 3.15 / 2

Molarity = 1.57

d) 15.25 g of Pb(C₂H₃O₂)₂ in 65 ml

Molar mass = 207 + 56 + 6 + 64 = 333 g

                  333 g ----------------- 1 mol

                   15.25 g -------------- x

                   x = 0.046 moles

Molarity = 0.046 / 0.065

Molarity = 0.71