Answer:
[tex]\large \boxed {8.48 \times 10^{22}\text{ atoms}}[/tex]
Explanation:
1 mol of Pb(MnO₄)₂contains 1 mol of Pb atoms.
1. Moles of Pb
[tex]\text{Moles of Pb} = \text{62.7 g Pb(MnO$_{4}$)}_{2} \times \dfrac{\text{1 mol Pb(MnO$_{4}$)}_{2}}{\text{445.07 g Pb(MnO$_{4}$)}_{2}}\\\\\times \dfrac{\text{1 mol Pb}}{\text{1 mol Pb(MnO$_{4}$)}_{2}} = \text{0.1409 mol Pb}[/tex]
2. Atoms of Pb
[tex]\text{Atoms of Pb} = \text{0.1409 mol Pb } \times \dfrac{ 6.022 \times 10^{23}\text{ atoms Pb }}{\text{1 mol Pb }}\\\\= \large \boxed {\mathbf{8.48 \times 10^{22}}\textbf{ atoms Pb }}[/tex]
