Samantha has 3/4 as many colored pencils as Carl Carl has 4/5 as many color pencils as Maurice if they have 96 colored pencils altogether how many fewer colored pencils does Samantha have the Morris

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Answer:

16 colored pencils.

Step-by-step explanation:

Let x represent the number of pencils that Maurice has.

We have been given that Carl has 4/5 as many color pencils as Maurice, so Carl have [tex]\frac{4}{5}x[/tex] pencils.

We are also told that Samantha has 3/4 as many colored pencils as Carl, so Samantha would have [tex](\frac{4}{5}x)\cdot \frac{3}{4}=\frac{3}{5}x[/tex] pencils.

Since have 96 colored pencils altogether, so we will equate sum of all pencils with 96 as:

[tex]x+\frac{4}{5}x+\frac{3}{5}x=96[/tex]

[tex]\frac{5}{5}x+\frac{4}{5}x+\frac{3}{5}x=96[/tex]

[tex]\frac{5+4+3}{5}x=96[/tex]

[tex]\frac{12}{5}x=96[/tex]

[tex]\frac{5}{12}\times \frac{12}{5}x=96\times\frac{5}{12}[/tex]

[tex]x=8\times5[/tex]

[tex]x=40[/tex]

Now, we will subtract [tex]\frac{3}{5}x[/tex] from x of 40 as:

[tex]x-\frac{3}{5}x[/tex]

[tex]40-\frac{3}{5}(40)[/tex]

[tex]40-3(8)[/tex]

[tex]40-24=16[/tex]

Therefore, Samantha has 16 fewer colored pencils than Morris.

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