Would any one know how to solve this arithmetic series on the number of magic squares created per order. n=order, A=integer, D=difference between terms. The solution is n=1,2,... are 1, 0, 1, 880, 275305224, ...

Would any one know how to solve this arithmetic series on the number of magic squares created per order norder Ainteger Ddifference between terms The solution i class=

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23al01

Answer:

Step-by-step explanation:

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0nyi

Answer

1.7761 * 10^19 (5*5 magic square estimation)

Step-by-step explanation:

Excluding rotations and reflections, there is exactly one 3×3 magic square, exactly 880 4×4 magic squares, and exactly 275,305,224 5×5 magic squares. 778-783 gives the 880 4 X 4 squares.

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Given an n×nn×n magic square, write MnMn for its magic constant. There are nn rows, each of which has sum MnMn, so the sum of all the entries in the square is n⋅Mnn⋅Mn. Each whole number between 11 and n2n2 appears once, so

nMn=1+2+…+n2=n2(n2+1)2,Mn=n(n2+1)2.

nMn=1+2+…+n2=n2(n2+1)2,Mn=n(n2+1)2.

In particular, every n×nn×n magic square has the same constant.

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