Question

Jason has two bags with 6 tiles each. The tiles in each bag are shown below:

1 2 3 4 5 6

Without looking, Jason draws a tile from the first bag and then a tile from the second bag. What is the probability of Jason drawing an even tile from the first bag and an even tile from the second bag?

6/12
9/12
6/36
9/36

Answer 1

Option D is the correct answer .

Step-by-step explanation:

Step 1 :

Given ,

Number of tiles in each bags = 6

Number of even number tiles in each bag = 3

We need to find  probability of drawing even tile from both the bags

Step 2 :

The probability of drawing an even tile from the first bag = $\frac{3}{6}$

The probability of drawing an even tile from the second bag = $\frac{3}{6}$

The probability  of drawing an even tile from the first bag and then from the second bag  =  $\frac{3}{6}$ × $\frac{3}{6}$  =  $\frac{9}{36}$

Step 3 :

Answer :

The probability of drawing even tiles from both the bags = $\frac{9}{36}$

Option D is the correct answer.