The solution of the equations are (2,1)
Explanation:
The given equations are
[tex]3x+4y=10[/tex] ----------(1) and
[tex]2x+3y=7[/tex] ---------(2)
We need to determine the solution of the equation using elimination method.
Multiplying the equation [tex]3x+4y=10[/tex] by 2, we get,
[tex]6x+8y=20[/tex] -------(3)
Multiplying the equation [tex]2x+3y=7[/tex] by -3, we get,
[tex]-6x-9y=-21[/tex] -------(4)
Adding the equation (3) and (4), we have,
[tex]\ \ \ 6x+8y=20\\-6x-9y=-21\\--------\\-y=-1[/tex]
[tex]y=1[/tex]
Thus, the value of y is 1
Substituting the value of y in equation (1), we have,
[tex]3x+4(1)=10[/tex]
[tex]3x+4=10[/tex]
[tex]3x=6[/tex]
[tex]x=2[/tex]
Thus, the value of x is 2.
Hence, the solution of the equation is (2,1)