Answer:
The value of height of the building h = 509.2 feet
Step-by-step explanation:
From the Δ A B C
[tex]\tan 25 = \frac{h}{y}[/tex]
⇒ h = y [tex]\tan 25[/tex]° ------- (1)
From Δ A B D
[tex]\tan 20 = \frac{h}{y + 300}[/tex]
⇒ h = ( y + 300 ) [tex]\tan20[/tex]° ------- (2)
Equation 1 = Equation 2
⇒ y [tex]\tan 25[/tex]° = ( y + 300 ) [tex]\tan20[/tex]°
⇒ 0.46 y = 0.36 y + 109.2
⇒ 0.1 y = 109.2
⇒ y = 1092 feet
Put this value of y in equation ( 1 ) we get,
⇒ h = 1092 × tan 25°
⇒ h = 509.2 feet
This is the value of height of the building.