The solution is (1,0)
Explanation:
The two equations are [tex]3x+16y=3[/tex] and [tex]3x-16y=3[/tex]
We need to solve the equation using elimination method.
Adding the two equations, we get,
[tex]3x+16y=3\\3x-16y=3\\-------\\6x=6[/tex]
[tex]x=1[/tex]
Thus, the value of x is 1
Substituting [tex]x=1[/tex] in the equation [tex]3x+16y=3[/tex] , we get,
[tex]3(1)+16y=3[/tex]
Simplifying, we get,
[tex]16y=3-3[/tex]
[tex]16y=0[/tex]
[tex]y=0[/tex]
Thus, the value of y is 0.
The solution is (1,0)