Answer:
[tex]7\frac{3}{8} \ miles[/tex]
Step-by-step explanation:
Given:
After lunch the friends walked 6 3/4 miles before arriving at the end of the trail.
The trail is 14 1/8 miles long.
Question asked:
How long did the friends walk before lunch ?
Solution:
Let the friends walk before lunch in miles = [tex]x[/tex]
As total length of trail is given [tex]14\frac{1}{8}\ miles[/tex] , we can conclude:
Total length of trail = The friends walk before lunch in miles + The friends walk after lunch in miles
[tex]14\frac{1}{8} =x+6\frac{3}{4} \\ \frac{14\times8+1}{8}=x+\frac{6\times4+3}{4} \\\frac{113}{8} =x+\frac{27}{4}[/tex]
Subtracting both side by [tex]\frac{27}{4}[/tex]
[tex]\frac{113}{8} -\frac{27}{4} =x+\frac{27}{4}-\frac{27}{4}[/tex]
Taking LCM of 4 and 8 ,we get 8
[tex]\frac{113-54}{8} =x\\\\\frac{59}{8} =x\\\ \\7\frac{3}{8} = x[/tex]
Therefore, the friends walk before lunch is [tex]7\frac{3}{8} \ miles[/tex].