Question

How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of
NaC2H3O2 = 82.04 g/mol)

Answer 1

Answer:

78.96 g of NaC2H3O2

Explanation:

We are given;

• Volume of the solution as 350 mL
• Molarity of the solution as 2.75 M
• Molar mass of the solute NaC2H3O2 as 82.04 g/mol

We are required to determine the mass of the solute;

First we determine the number of moles;

Moles = Molarity × Volume

Therefore;

Moles of the solute = 2.75 M × 0.350 L

                                = 0.9625 moles

Second, we determine the mass

Mass = Moles × Molar mass

        = 0.9625 moles × 82.04 g/mol

        = 78.9635 g

        = 78.96 g

Therefore, the mass of NaC2H3O2 needed is 78.96 g