Question

a 4.50 g nugget of pure gold absorbed 276 J of heat. the initial temperature was 25.0 degrees C. what was the final temperature?

Answer 1

500.45° C is the final temperature when a 4.50 g nugget of pure gold absorbed 276 J of heat. The initial temperature was 25.0 degrees C.

Explanation:

Data given:

q = 276 J/ grams °C (Heat absorbed)

m = 4.50 grams or

c = 0.129 joules

initial temperature  = 25 °C

Final temperature = ?

From the equation

q = m (ΔT) C  

change in temperature = $\frac{q}{mc}$

Putting the values in above simplified equation:

change in temperature = $\frac{276}{4.5 x .129}$

    = 475.45 ° C.

To calculate final temperature following equation is used:

( change in temperature = final temperature- initial temperature)

475.45 + 25 = final temperature

500.45 = final temperature

Answer 2

The final temperature of the heat will be "500.45°C".

Heat and temperature

According to the question,

Heat absorbed, q = 276 J/g°C

Mass, m = 4.50 g

Initial temperature = 25°C

We know the equation,

→q = m ΔT C

Change in temperature (ΔT) be:

= $\frac{q}{mC}$

By substituting the values,

= $\frac{276}{4.50\times 129}$

= 475.45°C

hence,

The final temperature will be:

→ Change in temperature = Final temperature - Initial temperature

or,

Final temperature = 475.45 + 25

                              = 500.45°C

Thus the above response is correct.

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