Answer:
C. (0, -3)
Step-by-step explanation:
The given system is
[tex] - 2x - 3 \leqslant y[/tex]
[tex]y - 1 \: < \: \frac{1}{2} x[/tex]
The point that satisfies both inequalities is the solution to the system.
When x=0 and y=-3.
We substitute into the first inequality to get:
[tex] - 2(0) - 3 \leqslant - 3 \\ - 3 \leqslant - 3...true[/tex]
We again substitute into the second inequality to get:
[tex] - 3- 1 \: < \: \frac{1}{2} (0) \\ - 4 \: < \: 0....true[/tex]
The point (0,-3) is a solution to the system of inequalities.