Question

(25 Points & Brainliest)
Let f(x) = 4x3 + 3x2 − 20x − 15 and g(x) = 4x + 3.

Find f(x) over g (x)

A) x2 − 5
B) 4x2 + x
C) x2 − 5x
D) 4x2 + 12

Answer 1

Answer:

A

Step-by-step explanation:

first you have to factor f(x) by grouping. You factor out an x^2 out of the (4x3 + 3x2) and then you factor out a -5 from (− 20x − 15). this gives you the factors of (x^2-5) and (4x+3). since their is a 4x+3 on the bottom as g(x), you can cancel it with the one on the top, leaving x2 − 5 left.

Answer 2

Answer:

$x^{2} -5$