Option D: [tex](2,0) \text { and }(-3,5)[/tex] is the solution to the system of equations.
Explanation:
Given that the system of equations are [tex]x=2-y[/tex] and [tex]y=x^{2} -4[/tex]
We need to determine the solution to the system of equations graphically.
Let us consider plotting the equation [tex]x=2-y[/tex] in the graph.
First, we shall determine the x and y intercepts for the equation [tex]x=2-y[/tex]
When [tex]x=0[/tex], we get,
[tex]0=2-y[/tex]
[tex]2=y[/tex]
Similarly, when [tex]y=0[/tex], we get,
[tex]x=2-0[/tex]
[tex]x=2[/tex]
Thus, let us join the coordinates [tex](0,2)[/tex] and [tex](2,0)[/tex] to get the equation of the line.
Let us consider plotting the equation [tex]y=x^{2} -4[/tex] in the graph.
When [tex]x=0[/tex] ⇒ [tex]y=-4[/tex]
When [tex]y=0[/tex] ⇒ [tex]x=\pm2[/tex]
Thus, let us join the coordinates [tex](0,-4)[/tex], [tex](2,0)[/tex] and [tex](-2,0)[/tex] to get the equation of the parabola.
The solution of the two equations is the point of intersection of these two lines.
Hence, the lines intersect at the points [tex](2,0) \text { and }(-3,5)[/tex]
Therefore, Option D is the correct answer.
The image of the solution is attached below: