Question

A line passes through the points (-6, -7) and (-2, 1). The equation of this line can be expressed as y = mx + b, where m and b are integers.

Answer 1

Answer:

• $m=2$

• $b=5$

Step-by-step explanation:

As a line passes through the points

• (-6, -7) and

• (-2, 1)

$\mathrm{Slope\:between\:two\:points}:\quad \mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(-2,\:1\right)$

$m=\frac{1-\left(-7\right)}{-2-\left(-6\right)}$

$m=2$

As the equation of the line in slope-intercept form be

$y = mx + b$

Putting the point (-6, -7) and m = 2 in slope-intercept form

$y = mx + b$

$\left(-7\right)=\left(2\right)\left(-6\right)+b$

$-2\cdot \:6+b=\left(-7\right)$

$-12+b=-7$

$b=5$

Therefore,

• $m=2$

• $b=5$