Answer:
The other endpoint of the line segment = (-1, -3)
Step-by-step explanation:
A segment has:
Let (x, y) be the other endpoint of the line segment
[tex]\frac{\left(1\:+\:x\right)}{2}=0[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}2[/tex]
[tex]\frac{2\left(1+x\right)}{2}=0\cdot \:2[/tex]
[tex]1+x=0[/tex]
[tex]x=-1[/tex]
[tex]\frac{\left(3+y\right)}{2}=0[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}2[/tex]
[tex]\frac{2\left(3+y\right)}{2}=0\cdot \:2[/tex]
[tex]3+y=0[/tex]
[tex]y=-3[/tex]
Therefore, the other endpoint of the line segment = (-1, -3)