Question

A special deck of cards has 3 blue cards, and 7 orange cards. The blue cards are numbered 1, 2, and 3. The orange cards are numbered 1, 2, 3, 4, 5, 6 and 7. The cards are well shuffled and you randomly draw one card.
B = card drawn is blue
O = card drawn is odd-numbered

a. How many elements are there in the sample space? ____

b. P(B) = _____

Answer 1

Answer:

A.. Number of elements in the sample space is 10.

B.. Given that event B is card drawn is blue.

Step-by-step explanation:

Special deck has3 blue and 7 orange cards. The blue cards are numbered 1, 2 and 3. The orange cards are numbered 1, 2, 3, 4, 5, 6 and 7.

We draw one card randomly from the deck, the sample space is

S={b1, b2, b3, o1, o2, o3, o4, o4, o6, o7}

Where,

'b' represents blue card

And 'o' represents orange cards.

Number of elements in the sample space is 10.

Given that event B is card drawn is blue.

B={b1, b2, b3}.

Answer 2

We will see that the sample space is  {B1, B2, B3, B4, B5, B6, B7, O1, O2, O3} and P(B) = 7/10.

How to find the elements in the sample space?

There are 10 cards, 3 orange ones, and 7 blue ones, all of them numbered. Then the sample space is just the cards.

{B1, B2, B3, B4, B5, B6, B7, O1, O2, O3}

Where these elements represent:

B2 = Blue card with number 2.

Finding the probability of getting a blue card?

We want to get P(B), which is the probability of getting a blue card, this is equal to the quotient between the number of blue cards and the total number of cards.

P(B) = 7/10

If you want to learn more about probability, you can read:

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