Answer:
The restrictions will be:
x ≠ 0;
x² ≠ 0 ⇒ x ≠ 0 ;
5x² ≠ 0 ⇒ x² ≠ 0 ⇒ x ≠ 0;
Step-by-step explanation:
As we know that
There are two genuine reasons why domains are restricted.
We cannot divide the expression by 0 as it would be undefined then.
We cannot take the square root of a negative number, as the result will not be a defined.
Considering the expression
[tex]\frac{4}{x}+\frac{1}{x^2}=\frac{1}{5x^2}[/tex]
As we can not put x = 0 in the denominator as it would make the expression undefined.
In other words, the certain values which make the denominator equal to zero for a rational expression will be restricted values.
Hence, the restrictions will be:
x ≠ 0;
x² ≠ 0 ⇒ x ≠ 0 ;
5x² ≠ 0 ⇒ x² ≠ 0 ⇒ x ≠ 0;