Respuesta :
Answer:
a) V = 30j
b) U = 475i
c) W = 475i + 30j
d) true speed = 475.95mi/h
e) Direction = 3.62°
Explanation:
The speed of the jet is 475mi/h relative to air.
The wind speed is 30mi/h to the north.
a) The velocity of the wind represented by a ve tor v in component form is given by:
V = 30j
b) The velocity of the jet relative to the air represented by a vector U in component form is given by:
U = 475i
c) The true velocity of the jet as a vector W is represented as W is given by:
W = U + V = 475i + 30j
d) The true speed of the jet is given by:
W = Sqrt(475^2 +30^2)
W = Sqrt(225625 + 900)
W = Sqrt(226525)
W = 475.95mi/h
e) The direction of the jet is given by :
Theta = Tan^-1 (30/475)
Theta = Tan^-1(0.06316)
Theta = 3.62°
The vector form of the motion of the jet and wind indicates both the direction and magnitude of the motion.
The correct responses are;
- a. Velocity of the wind as a vector component form is 30·j
- b. Velocity of the jet as a vector component form is 475·i
- c. The true velocity of the jet as a vector is 475·i + 30·j
- d. The jet speed is approximately 475.95 mi/h
- e. The direction of the jet is approximately east 3.164° north
Reasons:
The direction of the jet = Due East
The relative velocity of the jet = 475 mi/h
Direction of the wind = North
Assumptions: i vector is in the eastern direction
j vector is in the northern direction
a. Required: Velocity of the wind in vector form
Solution:
Direction of the wind = North
Unit vector in the northern direction = j
Therefore;
Velocity of the wind as a vector component form, [tex]\vec{v}_{wind}[/tex] = 30·j
b. Required: Velocity of the jet relative to the air in vector form
Solution:
Direction of the jet = East
Unit vector in the eastern direction = i
Therefore;
Velocity of the jet as a vector component form, [tex]\mathbf{\vec{v}_{jet}}[/tex] = 475·i
c. The jet is moved by the wind as the wind blows north
The true velocity of the jet = Velocity of wind + Velocity of the jet relative to the air
Therefore;
The true velocity of the jet as a vector, [tex]\vec{v}_{tvj}[/tex] = 475·i + 30·j
d. The speed of the jet is given by the magnitude of the true velocity vector, |v|, as follows;
|v| = √(475² + 30²) + = √(226,525) = 5·√9061 ≈ 475.95
Jet speed, |v| ≈ 475.95 mi/h (475.95 mi/h)
e. The direction of the jet relative to the positive x-axis, is found by finding the direction of the true velocity of the jet as a vector, as follows;
[tex]\theta = arctan \left(\dfrac{Component \ in \ the \ \mathbf{j} \ direction}{Component \ in \ the \ \mathbf{i} \ direction} \right) = arctan \left(\dfrac{30}{475} \right) \approx 3.614^{\circ}[/tex]
Therefore;
The direction of the jet , θ ≈ East 3.164° North
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