Answer:
The momentum after the collision is [tex]-12kg\cdot m/s[/tex].
The momentum of the red cart after the collision is [tex]-57 kg\cdot m/s[/tex]
The velocity of the red cart after the collision is [tex]-4.75m/s[/tex].
Explanation:
The law of conservation of momentum says that momentum before the collision must equal the momentum after the collision; therefore, the momentum after the collision equals [tex]-12kg\cdot m/s[/tex] (which is the momentum before the collision).
After the collision, the conservation of momentum demands that
[tex](12kg)v+(20kg)(2.25m/s) = -12kg\cdot m/s[/tex]
[tex](12kg)v = -12(kg\cdot m/s)- 45 (kg\cdot m/s)[/tex]
[tex]v = \dfrac{-12(kg\cdot m/s)- 45 (kg\cdot m/s)}{12kg}[/tex]
[tex]\boxed{v = -4.75m/s}[/tex]
which is the velocity of the red cart after the collision.
Finally, the momentum of the red cart is after the collision is
[tex]P_{red \: cart} = (12kg)(-4.75m/s)[/tex]
[tex]\boxed{P_{red \: cart} = -57kg\cdot m/s}[/tex]
Thus, the total momentum after the collision is [tex]-12kg\cdot m/s[/tex], and of the red cart is [tex]-57 kg\cdot m/s[/tex], and the velocity of the red cart after the collision is [tex]-4.75m/s[/tex].