Question

Find x for,
sin⁻¹ 4x + sin⁻¹ 3x = -$\frac{\pi }{2}$

Answer 1

Explanation:

Let's solve this problem graphically. Here we have the following equation:

$sin^{-1}(4x) + sin^{-1}(3x) = -\frac{\pi}{2}$

So we can rewrite this as:

$f(x)=sin^{-1}(4x) + sin^{-1}(3x) \\ \\ g(x)= -\frac{\pi}{2}$

So the solution to the equation is the x-value at which the functions f and g intersect. In other words:

$f(x)=g(x) \\ \\ sin^{-1}(4x) + sin^{-1}(3x) = -\frac{\pi}{2}$

Using graphing calculator, we get that this value occurs at:

$\boxed{x=-0.2}$