Can someone please help me answer this math question?

Answer:
x = 10
Step-by-step explanation:
The line from the vertex to the base is a perpendicular bisector.
Consider the left side right triangle, eith base = [tex]\frac{1}{2}[/tex] x
Using Pythagoras' identity.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
([tex]\frac{1}{2}[/tex] x )² + 7² = ([tex]\sqrt{74}[/tex] )², that is
[tex]\frac{1}{4}[/tex] x² + 49 = 74 ( subtract 49 from both sides )
[tex]\frac{1}{4}[/tex] x² = 25 ( multiply both sides by 4 to clear the fraction )
x² = 100 ( take the square root of both sides )
x = [tex]\sqrt{100}[/tex] = 10
Answer:
x = 10 units.
Step-by-step explanation:
The 2 triangles are congruent by SAS.
Therefore the line of length x is bisected by the perpendicular line,
and they are both right triangles, so we can apply the Pythagoras theorem.
√74)^2 = 7^2 + (0.5x)^2
(0.5x)^2 = 74 - 49
0,25x^2 = 25
x^2 = 25/0.25
x^2 = 100
x = 10 (answer)