Question

The following unbalanced chemical equation is:

2 atoms of H + 2 atoms of I yields 1 atom of H and 1 atom of I

Write a balanced equation for this reaction using the smallest coefficients possible.

Answer 1

Answer:

H2 + I2 —> 2HI

Explanation:

From the information provided, the equation can be written as:

H2 + I2 —> HI

Now, the equation can be balance as follows:

There are 2 atoms of H on the left side and 1atom on the right. It can be balance by putting 2 in front of HI as shown below:

H2 + I2 —> 2HI

Now the equation is balanced as there are equal numbers of atoms of the different elements present on both sides of the equation

Answer 2

Answer:

$H_{2} + I_{2} ----> 2HI$

Explanation:

Given the following reactants;

Two(2) atoms of Hydrogen, H

Two(2) atoms of Iodine, I

$H_{2} + I_{2} ----> HI$

Now, we will balance the above equation with the smallest coefficients possible;

$H_{2} + I_{2} --->H_{2}+2I-->I..H..H..I----> 2HI$

In the reaction above, Hydrogen and Iodine reacts to form a chemical compound called Hydrogen Iodide.

$I_{2}$ first dissociates into 2 iodine atoms, which each attach themselves to a side of an $H_{2}$ molecule and break the Hydrogen-Hydrogen bond.