[tex]\frac{23\pi}{3}[/tex] corresponds to [tex]\left(\frac{1}{2},-\frac{\sqrt{3}}{2}\right)[/tex].
[tex]-\frac{3\pi}{4}[/tex] corresponds to [tex]\left(-\frac{\sqrt{2}}{2},-\frac{\sqrt{2}}{2}\right)[/tex].
-150 degree corresponds to [tex]\left(-\frac{\sqrt{3}}{2},\frac{1}{2}\right)[/tex].
Rewrite as:
[tex]\frac{23\pi}{3}=\frac{18\pi+5\pi}{3}=6\pi+\frac{5\pi}{3}[/tex].
We know that [tex]\frac{5\pi}{3}[/tex] corresponds to [tex]\left(\frac{1}{2},-\frac{\sqrt{3}}{2}\right)[/tex]. So [tex]\frac{23\pi}{3}[/tex] also corresponds to [tex]\left(\frac{1}{2},-\frac{\sqrt{3}}{2}\right)[/tex].
[tex]-\frac{3\pi}{4}[/tex] has same position as: [tex]-\frac{3\pi}{4}+2\pi=\frac{5\pi}{4}[/tex].
So the corresponding point to it is [tex]\left(-\frac{\sqrt{2}}{2},-\frac{\sqrt{2}}{2}\right)[/tex].
From unit circle 150 degree corresponds to [tex]\left(-\frac{\sqrt{3}}{2},\frac{1}{2}\right)[/tex].
Learn more: https://brainly.com/question/16236436