Answer:
Activation energy for the rotting reaction is 4.805 x 10⁻⁶ kJ/mol
Explanation:
Use the Arrhenius equation applied for two temperatures:
Ea = R· ln(k2/k1) · (1/T1 – 1/T2)
Where
R= 8.314x10-3kJ/(mol.K)
k2/k1 = 2.5/17 = 0.147 ∴ ln(k2/k1) = - 1.92
(1/T1 – 1/T2) = 1/298K – 1/273.5K = - 0.000301 K-1
Ea = 8.314x10⁻³ x (- 1.92) x (- 0.000301 K-1)
= 4.805 x 10⁻⁶ kJ/mol