Answer: the probability of putting less than 33 ounces in a cup is 0.98
Step-by-step explanation:
Since the machine's output is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = outputs of the machine.
µ = mean output
σ = standard deviation
From the information given,
µ = 25 ounces
σ = 4 ounces
The probability of putting less than 33 ounces in a cup is expressed as
P(x < 33)
For x = 33,
z = (33 - 25)/4 = 2
Looking at the normal distribution table, the probability corresponding to the z score is 0.98
