Question

What is the equation of a line through the points (0,9) and (3, 0)?
9-0
O because m= 0-3 y=-3x + 9
9-0
o because m= 0-3; y=-3x + 3
because m-8-9:y=-3x+9
3-
O because m= nug: Y
X+3

Answer 1

Option A: The equation of a line is $y=-3x+9$

Explanation:

Given that the two points are $(0,9)$ and $(3,0)$

We need to determine the equation of the line that passes through the points $(0,9)$ and $(3,0)$

The equation of the line can be determined using the formula,

$y-y_1=m(x-x_1)$

First, we shall determine the value of the slope m.

Let us substitute the coordinates $(0,9)$ and $(3,0)$ in the slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

Thus, we have,

$m=\frac{0-9}{3-0}$

$m=\frac{-9}{3}$

$m=-3$

Now, we shall substitute the slope  $m=-3$ and the point $(3,0)$ in the formula $y-y_1=m(x-x_1)$, we get,

$y-0=-3(x-3)$

Simplifying, we get,

$y=-3x+9$

Thus, the equation of the line is $y=-3x+9$

Therefore, Option A is the correct answer.