Respuesta :
Answer:
[tex]4U_0[/tex]
Explanation:
We are given that
Amount of work needed to bring a point charge q0 from infinity to a point P=[tex]U_0[/tex]
We know that potential at point P=[tex]V=\frac{U}{q}[/tex]
[tex]U=Vq[/tex]
Where U=Amount of work needed to bring a point charge q from infinity to a point P
Initially ,[tex]V=\frac{U_0}{q_0}[/tex]
New charge, q=[tex]4q_0[/tex]
Then, work done,U=[tex]\frac{U_0}{q_0}\times (4q_0)=4U_0[/tex]
Hence, the amount of work needed to bring a new charge 4q0 from infinity to point P=[tex]4U_0[/tex]
Answer:
[tex] 4U_{0} [/tex]
Explanation:
V = u / q,
Work = P = V
1U / 1/4 = 4U