Question

An LED with total power P tot = 960 mW Ptot=960 mW emits UV light of wavelength 360 nm. Assuming the LED is 45% efficient and acts as an isotropic point source (i.e., emits light uniformly in all directions), what is the amplitude of the electric field, E 0 E0 , at a distance of 2.0 cm from the LED?

Answer 1

Answer:

V =c/wavelenth

C = 960 ×45/100 =432MW

V = 432 /360 = 1.2volt

But E = v/d

E= 1.2/ 2 = 0.6volt.