Starting with a population of genetically identical mice, you discover two new independent mutant strains in which all of the animals have epileptic seizures. In both strains, you know that the epileptic seizures are due to a single DNA mutation. You cross a mutant mouse from one strain to a mutant mouse from the second strain and find that none of their offspring undergo spontaneous seizures. From this experiment you would conclude that the two mutant strains of mice most likely have mutations in:

a-the same DNA base position within a particular gene
b-the same gene, but not necessarily the same DNA base position.
c-two different genes.

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Answer:

B - the same gene, but not necessarily the same DNA base position. They do not show seizures when they are crossed, but show seizures in independent populations.

When they are not in the same position and hence they do not come together to express the  disease.

Thus, the answer is B Explanation

a. If they are in the same DNA base positions,, their offspring might have expressed epileptic seizures.

c. If they are from different genes it would have interfered with the trait.

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