Hydrogen and chlorine atoms react to form a simple diatomic molecule in a 1:1 ration, that is HCl. The percent isotopic abundances of the chlorine isotopes 35Cl and 37Cl are 75.77% and 24.23%, respectively. The percent isotopic abundances of the hydrogen isotopes are 2H and 3H are 0.015% and 0.001%. (a) How many different HCl molecules are possible, and what are their mass numbers

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Answer:

Four different HCl molecules are possible.

  1. Mass of [tex]^{2}H^{35}Cl[/tex]  = 37 amu
  2. Mass of [tex]^{3}H^{35}Cl[/tex] =  38 amu
  3. Mass of [tex]^{2}H^{37}Cl[/tex] = 39 amu
  4. Mass of [tex]^{3}H^{37}Cl[/tex] = 40 amu

Explanation:

Mass of 2-H isotope = 2 amu

Mass of 3-H isotope = 3 amu

Mass of 35-Cl isotope = 35 amu

Mass of 37-Cl isotope = 37 amu

Different HCl molecules possible are:

1) [tex]^2H+^{35}Cl\rightarrow ^{2}H^{35}Cl[/tex]

Mass of [tex]^{2}H^{35}Cl[/tex] = 2 amu + 35 amu = 37 amu

2)  [tex]^3H+^{35}Cl\rightarrow ^{3}H^{35}Cl[/tex]

Mass of [tex]^{3}H^{35}Cl[/tex] = 3 amu + 35 amu = 38 amu

3) [tex]^2H+^{37}Cl\rightarrow ^{2}H^{37}Cl[/tex]

Mass of [tex]^{2}H^{37}Cl[/tex] = 2 amu + 37 amu = 39 amu

4) [tex]^3H+^{37}Cl\rightarrow ^{3}H^{37}Cl[/tex]

Mass of [tex]^{3}H^{37}Cl[/tex] = 3 amu + 37 amu = 40 amu

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