Respuesta :
Answer:
x= 2 and y = -4
Step-by-step explanation:
8x + 3y = 4 ---------------------------------(1)
-7x + 5y = -34 -----------------------------(2)
Multiply through equation (1) by 5 and multiply through equation(2) by 3
40x + 15y = 20 ----------------------------(3)
-21x + 15y =-102----------------------------(4)
Subtract equation (4) from equation (3)
61x = 122
Divide both-side of the equation by 61
61x/61 = 122/61
(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)
x = 122/61
x=2
Substitute x= 2 into equation (1)
8x + 3y = 4
8(2) + 3y = 4
16 + 3y = 4
Subtract 16 from both-side of the equation
16-16 + 3y = 4-16
3y = -12
Divide both-side of the equation by 3
3y/3 = -12/3
y = -4
x= 2 and y = -4
Answer:
[tex]x=2\\\\y=-3[/tex]
Step-by-step explanation:
Given Equations:
[tex]8x+3y=4[/tex] Equation :1
[tex]-7x+5y=-34[/tex] Equation:2
In elimination method, we makes the coefficient of any one variable same and eliminate them to get the solution in terms of the other variable.
Multiplying Equation:1 by '5' and Equation:2 by '3'
[tex]40x+15y=20[/tex] Equation:3
[tex]-21x+15y=-102[/tex] Equation:4
Subtracting Equation:4 From Equation:3
[tex](40x+15y)-(-21x+15y)=20-(-102)[/tex]
[tex]40x+15y+21x-15y=20+102[/tex]
Adding the coefficients of same variables:
[tex]61x=122\\\\x=\frac{122}{61} \\\\x=2[/tex]
Putting the value of 'x' in Equation:1 to find the value of 'y'
[tex]8x+3y=4[/tex]
[tex]8(2)+3y=4\\\\16+3y=4[/tex]
Subtracting '16' both the sides:
[tex]3y=4-16\\\\3y=-12\\\\[/tex]
Dividing by '3' both the sides:
[tex]y=\frac{-12}{3}\\ \\y=-3[/tex]
So the solution of the equations is:
[tex]x=2\\\\y=-3[/tex]
