Question

Use the method of completing the square to transform the quadratic equation into the form $(x-p)^2=q$

$9-9x+x^2=0$

Answer 1

$9-9x+x^2=0$

$3^2-9x+x^2=0$

Notice that:

$(3-x)^2=9-6x+x^2$

Now we will write  $3^2-9x +x^2$  in a different way:

$3^2-6x-3x+x^2=0$

$3^2-6x+x^2=3x$

$(3-x)^2=3x$