Answer:
[tex]V(t)=130\sqrt{2}\sin(130\pi t)V[/tex]
Explanation:
[tex]V_r[/tex] = RMS voltage = 130 V
f = Frequency = 65 Hz
Instantaneous voltage is given by
[tex]V=\sqrt{2}V_r\sin(2\pi ft+\phi)[/tex]
[tex]\\\Rightarrow V(t)=130\sqrt{2}\sin(2\pi 65t+\phi)\\\Rightarrow V(t)=130\sqrt{2}\sin(130\pi t+\phi)[/tex]
at t = 0 v = 0
[tex]V(0)=130\sqrt{2}\sin(130\pi \times 0+\phi)\\\Rightarrow 0=130\sqrt{2}\sin(130\pi \times 0+\phi)\\\Rightarrow sin\phi=0\\\Rightarrow \phi=0[/tex]
So, the function is
[tex]V(t)=130\sqrt{2}\sin(130\pi t)V[/tex]