Question

Find the product of (4z^2 + 7z – 8) and (–z + 3).


The product of (4z^2 + 7z – 8) and (–z + 3) is –4z3 + [-19, -5, 5, 19]z^2 + [-29, -13, 13, 29]z – 24.

Answer 1

Answer:

5, 29 will both blank boxes

Step-by-step explanation:

the product of (4z^2 + 7z – 8) and (–z + 3)

(4z² + 7z – 8)(–z + 3)

-z(4z² + 7z – 8) + 3(4z² + 7z – 8)

-4z³-7z²+8z+12z²+21z-24

choose like terms

-4z³-7z²+12z²+8z+21z-24

-4z³+5z²+29z-24

5, 29