Question

A solution is prepared by mixing the 50 mL of 1 M NaH2PO4 with 50 mL of 1 M Na2HPO4. On the basis of the information, which of the following species is present in the solution at the lowest concentration?Extra ContentH3PO4 <--> H+ + H2PO4- Ka1 = 7.2 E-3H2PO4- <--> H+ + HPO42- Ka2 = 6.3 E-8HPO42- <--> H+ + PO43- Ka3 = 4.5 E-13answer options:A. PO43-B. H2PO4-C. HPO42-D. Na+

Answer 1

Answer:

A. PO43-

Explanation:

in the given is buffer . so H2PO4- and HPO42- both are present with equal concentration . Na+ is spectator ion it is also present in the concentration higher than the given species above .

but PO4-3 is not present . so it is lowest concentration

Answer 2

A buffer solution is a solution that does not change its ph by adding any components. The buffer solution contains:-

• Weak acids
• Conjugate base

The main function of the buffer solution is to resist the ph change in any circumstances.

According to the question, the components which make the solution buffer is $PO_4^{-3}$.

In the given is a buffer. so $H_2PO^4^-$and$HPO_4^2^-$ both are present with equal concentration. Na+ is a spectator ion it is also present in a concentration higher than the given species above but PO4-3 is not present. so it is the lowest concentration.

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https://brainly.com/question/18024346