[tex]\boldsymbol{\mathbf{Answer}}[/tex]
[tex]\boldsymbol{\mathbf{Machine \, A \,will\, take \,6 \,hours\, to \,produce\, 1 \,widget \,on\, its\, own.}}[/tex]
[tex]\boldsymbol{\mathbf{Step-by-step \,explanation:}}[/tex]
Let,
performance rate of machine A is x widget per hour.
performance rate of machine A is y widget per hour.
As given, Machine A and Machine B can produce 1 widget in 3 hours working together.
I.e mathemetically,
[tex]\boldsymbol{x + y=\frac{1}{3}......(1)}[/tex]
lly for second statement, Machine A’s speed were doubled, the two machines could produce 1 widget in 2 hours working together.
i.e mathematically,
[tex]\boldsymbol{2x + y=\frac{1}{2}......(2)}[/tex]
Substact equation (1) in (2)
[tex]x + y=\frac{1}{3}[/tex]
[tex]-2x + y=\frac{1}{2}[/tex]
Resultant equation will be,
[tex]-x=\frac{-1}{6}[/tex]
[tex]\boldsymbol{x = \frac{1}{6}}[/tex]
Performance rate of machine A is \frac{1}{6} widget per hour.
what is time Machine A will take to produce 1 widget on its own.
i.e = [tex]\frac{1}{\frac{1}{6}}[/tex]
[tex]\boldsymbol\mathbf{{=\, 6 \,hours.}}[/tex]