Question

A pilot can withstand an acceleration of up to 9g, which is about 88 m/s2, before blacking out. What is the acceleration experienced by a pilot flying in a circle of constant radius at a constant speed of 475 m / s if the radius of the circle is 1790 m

Answer 1

Answer:

a) centripetal acceleration= v^2/r

=475*475/3080=73.154 m/s^2

b) yes the pilot is okay because 73.154 m/s^2 is less than 9g.

Explanation:

Answer 2

Answer:

the acceleration experienced by a pilot flying in a circle is 126m/s²

Explanation:

Given that,

Speed of pilot, v = 475 m/s

Radius of the circle, r = 1790 m

If the pilot is moving in a circular path, it will experience a centripetal acceleration. It is given by the formula as :

The angular acceleration

a= ω²r

= v²/r.

Where v is tangential velocity and r is the radius.

a = v²/r.

$a=\dfrac{v^2}{r}a=\dfrac{(475\ m/s)^2}{1790\ m}a=126\ m/s^2$

So, the acceleration experienced by a pilot flying in a circle is 126m/s²