Respuesta :
Answer:
a) W = -213.26 J , b) T = 88.86 N , c) W = 313.6 N , d) N = 300.75 N , e♦1 F = 0
Explanation:
For this exercise we use Newton's second law, where the x axis is parallel to the plane and the y axis is perpendicular.
X axis
T - Wₓ = 0
T = Wₓ
Y Axis
N - Wy = 0
Let's use trigonometry to find the components
sin θ = Wₓ / W
cos θ = Wy / W
Wx = W sin θ
Wy = W cos θ
We substitute
T = W sin θ
N = W cos θ
Let's find the angle of the plane
sin θ = y / L
θ = sin⁻¹ 0.68 / 2.4
θ = 16.46º
a) The work of the force of man (T)
W = T L cos tea
W = mg sin 16.46 L cos θ
W = 32 9.8 2.4 sin 16.46 cos 180
W = -213.26 J
As the block slides at constant speed, the work of the block is of equal magnitude, but the component of the weight is parallel to the displacement, so the angle is zeroº.
W = 213.26 J
b) T = Wₓ
T = mg sin θ
T = 32 9.8 sin 16.46.
T = 88.86 N
c) the gravitational force is the weight of the block
W = mg
W = 32 9.8
W = 313.6 N
d) normal
N = W cos 16.46
N = 32 9.8 cos 16.46
N = 300.75 N
e) as the block moves with constant speed the acceleration is zero therefore the net force is zero
